Question 54306: Here is another question I need assistance with. You have a rectangle that is 2 cm more than twice its width and the perimeter is 52 cm, what are the dimensions of this rectangle?
Answer by fanks(6)   (Show Source):
You can put this solution on YOUR website! The rectangle has such edges: a, b, a, b where 
So the edges go like this: a, 2a + 2, a, 2a + 2
Their sum is  which is the same as the perimeter: 
Thus  and  , and 
One edge is 8cm, the other one is 18cm.
(Sorry, I misread the problem. Do I understand it correctly now - the rectangle's height is 2cm more than twice its width; that is rectangle's height is two times its width plus 2cm?)
The rectangle has such edges: a, b, a, b where 
So the edges go like this: a, a + 2, a, a + 2
Their sum is  which is the same as the perimeter: 
Thus  and  , and 
One edge is 12cm, the other one is 14cm.
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