Question 542888: Write equation in slope-intercept form for the line that passes through (5, 0) and is perpendicular to the line described by y=-5/2x +6
Answer by lmeeks54(111)   (Show Source):
You can put this solution on YOUR website! The slope-intercept form of an equation is:
y = mx + b, where:
m = the slope of the line
b = the y intercept (where x = 0)
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Given:
y = -5/2 x + 6
line passes through the point (5, 0). Note points are in the form (x, y)
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problem: find a line parallel to line given above. Parallel means has to have the same slope.
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When we have a point, like (5, 0), that means that point is a solution to the equation. We already know m (slope), x, and y, we need to solve for b to create our parallel line:
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Given:
m = -5/2 (or -2.5)
x = 5
y = 0
Find b
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0 = -5/2 (5) + b
0 = -12.5 + b
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add 12.5 to both sides:
12.5 = b
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Solution equation is:
y = -2.5 x + 12.5
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cheers,
Lee
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