SOLUTION: Use logarithmic identieties to write each expression as a single logarithm. The problem is: 2log4 - log6 + 3log2 I think that I got started out correctly but I am not sure

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Use logarithmic identieties to write each expression as a single logarithm. The problem is: 2log4 - log6 + 3log2 I think that I got started out correctly but I am not sure      Log On


   

Question 542681: Use logarithmic identieties to write each expression as a single logarithm.
The problem is:
2log4 - log6 + 3log2
I think that I got started out correctly but I am not sure if I did and if I did what to do after there. Below is where I stopped...
2log4 + 3log2/log6
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
write each expression as a single logarithm.
2log4 - log6 + 3log2
**
2log4 - log6 + 3log2
log4^2 - log6 + log2^3
addition in logs indicate multiplication; subtraction indicates division
log[(4^2*2^3)/6]=log(128/6)=log(64/3)
2log4-log6+3log2=log(64/3)