SOLUTION: To solve for this equation, {{{6x+5<11}}} or {{{3x-1>8}}} I would have to do the same to both sides correct? if I (-5) to the 11 side I must do the same to the 8 side right? From t

Algebra ->  Inequalities -> SOLUTION: To solve for this equation, {{{6x+5<11}}} or {{{3x-1>8}}} I would have to do the same to both sides correct? if I (-5) to the 11 side I must do the same to the 8 side right? From t      Log On


   



Question 54266This question is from textbook Algebra for College Students
: To solve for this equation, 6x%2B5%3C11 or 3x-1%3E8 I would have to do the same to both sides correct? if I (-5) to the 11 side I must do the same to the 8 side right? From there I would solve for x normally and that gives me the 2 answers? I think I have the logic down, just need to make sure my steps are correct.
Thank you
This question is from textbook Algebra for College Students

Found 3 solutions by Nate, stanbon, Edwin McCravy:
Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
6x+%2B+5+%3C+11
6x+%3C+6
x+%3C+1
or
3x+-+1+%3E+8
3x+%3E+9
x+%3E+3
<===) 1 --- 3 (===>

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
6x+5<11 or 3x-1>8
6x<6 OR 3x>9
x<1 OR x>3
Cheers,
Stan H.

Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
To solve for this equation,

    6x+5 < 11 OR 3x-1 > 8

I would have to do the same to both sides correct? 
if I (-5) to the 11 side I must do the same to the 
8 side right? From there I would solve for x normally 
and that gives me the 2 answers? I think I have the
logic down, just need to make sure my steps are
correct. 
Thank you
-----------------------------------------------------

First of all that is a two-part inequality, not an
"equation".

Solve each part separately

6x + 5 < 11  OR  3x - 1 > 8
    -5   -5          +1  +1
----------------------------
6x     < 6   OR  3x     > 9

Divide both sides of first by 6
Divide both sides of second by 3

     x < 1   OR       x > 3 

Graph: Since x can be either
left of 1 or else right of 3, we
shade everwhere x can be: 

<==============o-----o==========>
  -3 -2 -1  0  1  2  3  4  5  6

Interval notation:   (-oo, 1) U (3, oo)

Edwin