Question 542525: Hey, I'm really struggling with this exercise,
If |z|=2 and , determine the modulus and argument of
Thanks! Answer by KMST(5328) (Show Source):
You can put this solution on YOUR website! You must have been taught that multiplying numbers in polar form is easier, because all you have to do is multiply one modulus times the other and add the arguments. and
If you have not been taught anything about exponents on complex numbers, this problem is a way of introducing de Moivre's formula for the nth power of a complex number.