SOLUTION: How do I solve this equation? -3=12y-5(2y-7) I tried to solve it. But my teacher said i got it wrong. Here is how I tried to worked it out. -3=12y-5(2y-7) Original problem

Algebra ->  Distributive-associative-commutative-properties -> SOLUTION: How do I solve this equation? -3=12y-5(2y-7) I tried to solve it. But my teacher said i got it wrong. Here is how I tried to worked it out. -3=12y-5(2y-7) Original problem       Log On


   

Question 542377: How do I solve this equation? -3=12y-5(2y-7)
I tried to solve it. But my teacher said i got it wrong.
Here is how I tried to worked it out.
-3=12y-5(2y-7) Original problem
-3=12y-10y-35 Multiplied 2y and 7 by 5
32=12y-10y Added 35 to both sides
32=2y Combined like terms
16=y Divided both sides by 2
So what did I do wrong?
Found 2 solutions by rfer, friesr:
Answer by rfer(16322) About Me  (Show Source):
You can put this solution on YOUR website!
-3=12y-5(2y-7)
-3=12y-10y+35
-38=2y
y=-19

Answer by friesr(113) About Me  (Show Source):
You can put this solution on YOUR website!
-3=12y-5(2y-7) Original problem
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-3 = 12y - 10y + 35 (this is where your error was (-5*-7 = 35)
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-3 = 2y + 35
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-38 = 2y
---
y=-19
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