SOLUTION: I tried this problem, but the answer that I got doesn't seem right to me. Any help would be great! Write as a single logarithm (do not find approximations): 2 log 6 +log x-lo

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: I tried this problem, but the answer that I got doesn't seem right to me. Any help would be great! Write as a single logarithm (do not find approximations): 2 log 6 +log x-lo      Log On


   

Question 54183: I tried this problem, but the answer that I got doesn't seem right to me. Any help would be great!

Write as a single logarithm (do not find approximations): 2 log 6 +log x-log 3.
Here is what I tried: log 6^2 +log x - log 3
log 6^2+x/3 = log 36+x/3
Thank you for your help
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Write as a single logarithm:
2log%286%29+%2B+log%28x%29+-+log%283%29
First, you can apply the "product rule" for logarithms:

Now apply the "quotient rule" for logarithms:
log%28%28%286%5E2%29%28x%29%29%29-log%283%29+=+log%28%28%28%286%5E2%29%28x%29%29%2F3%29%29 = log%28%2836x%2F3%29%29+=+log%28%2812x%29%29