SOLUTION: At 1pm Tom leaves home on his bike heading to Sue's house at 9mph. An hour later, Sue leaves her house biking to Tom's at 6mph. Their houses are 39 miles apart. At what time will t
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-> SOLUTION: At 1pm Tom leaves home on his bike heading to Sue's house at 9mph. An hour later, Sue leaves her house biking to Tom's at 6mph. Their houses are 39 miles apart. At what time will t
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Question 54163: At 1pm Tom leaves home on his bike heading to Sue's house at 9mph. An hour later, Sue leaves her house biking to Tom's at 6mph. Their houses are 39 miles apart. At what time will the meet? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! At 1pm Tom leaves home on his bike heading to Sue's house at 9mph. An hour later, Sue leaves her house biking to Tom's at 6mph. Their houses are 39 miles apart. At what time will the meet?
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Tom DATA:
distance = x miles ; rate= 9 mph ; time= d/r=x/9 hrs.
Sue DATA:
distance = 39-x ; rate= 6 mph ; time = d/r = (39-x)/6
EQUATION:
Tom's time - Sue's time = 1 hr.
x/9 - (39-x)/6 = 1
6x -9(39-x) = 54
6x+9x-351 = 54
15x=405
x= 27 (Tom's distance is 27 miles)
At 9 mph this will take him 3 hours.
They will meet at 4 PM.
Cheers,
Stan H.
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