SOLUTION: Hello! i tried to solve this one but I am not sure if my answer is correct.
Chance of getting two 11's = 2 divided by sample space 21 = 2/21= 0.0952. Thanks!
Problem:
Giv
Algebra ->
Permutations
-> SOLUTION: Hello! i tried to solve this one but I am not sure if my answer is correct.
Chance of getting two 11's = 2 divided by sample space 21 = 2/21= 0.0952. Thanks!
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Giv
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Question 54140: Hello! i tried to solve this one but I am not sure if my answer is correct.
Chance of getting two 11's = 2 divided by sample space 21 = 2/21= 0.0952. Thanks!
Problem:
Given two six sided dice compute the probability of rolling two 11's in a row. Answer by funmath(2933) (Show Source):
You can put this solution on YOUR website! There are two ways of getting an 11 with 2 dice, (5,6) and (6,5).
There are 6*6=36 possible sums with two 6 dice.
So the probability of getting an 11 with two dies is 2/36=1/18.
Because you're finding the probability of two succesive rolls, you multiply the probability of getting the first 11 * the probabilty of getting the second 11.
P(11 and 11)=(1/18)(1/18)=1/324=.0031
Happy Calculating!!!
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