Question 54130This question is from textbook University of phoenix elementary and intermediate algebra
: 82. Tickets for a concert were sold to adults for $3 and to students $2. If the total receipts were $824 and twice as many adult tickets as students were sold, then how many of each were sold?
Write a system of two equations in two unknowns for each problem
This question is from textbook University of phoenix elementary and intermediate algebra
Answer by music974(43)   (Show Source):
You can put this solution on YOUR website! Well first we will start with what we know. Adults=3.00 and Students=2.00. Let us name adults a and students s. Now that we have figured out what we know lets make an equation. The first on can be 2s=a because when 2 is multiplied by the # of student tickets sold then we get the # of adult tickets sold. The other equation would be 2s + 3a =824. This is because when the # of tickets are multiplied by how much they cost and then added we should get 824. Now let's solve. We know a=2s so lets substitute that into the other equation to get 2s+2s(3)=824. Then we get 2s+6s=824. Add and get 8s=824. Divide both sides by 8 and get s=103.Now lets subtitute it into 2s=a to get how many adult tickets were sold. 2(103)=a, 206=a. Now let us check. 2(103)+3(206)=824, 206+618=824, 824=824. So 206 adult tickets were sold and 103 student tickets were sold.
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