SOLUTION: Find the ordered pairs for the x- and y- intercepts of the equation 4x + 2y = 16

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Question 541289: Find the ordered pairs for the x- and y- intercepts of the equation 4x + 2y = 16
Answer by friesr(113) About Me  (Show Source):
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y intercept:
4x + 2y = 16
2y = -4x + 16
y = -2x + 8
0 = -2x + 8
-8 = -2x
x = 4
(4,0)
X intercept:
4x = -2y + 16
x = (-1/2)y + 4
0 = (-1/2)y + 4
-4 = (-1/2)y
y = 8
(0,8)