SOLUTION: Hello, I am trying to figure out this geometric problem. Please help me. It states, In the Figure below, LJ is perpendicular-bisector of AF. What is the value of m + n.

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Question 54112: Hello,
I am trying to figure out this geometric problem. Please help me. It states, In the Figure below, LJ is perpendicular-bisector of AF. What is the value of m + n.
The figure is a triangle with line AJF at the bottom and it has 34 for AJ and 2m +3n for JF. The bisector is LJ making a 90 degree angle. Line LA is labeled 42 and line LF is labeled 3m. I hope this helps in solving the problem.
I started by writing 3m = 90 and got m=30 and 2m +3n = 90 where I put 30 in place of m and solved for n which was 20. My answer is m + n = 30 + 20 =50.
Thank you very much for taking the time to help me with this problem; we appreciate it very much.
Answer by venugopalramana(3286) (Show Source):
You can put this solution on YOUR website!
Hello,
I am trying to figure out this geometric problem. Please help me. It states, In the Figure below, LJ is perpendicular-bisector of AF. What is the value of m + n.
The figure is a triangle with line AJF at the bottom and it has 34 for AJ and 2m +3n for JF. The bisector is LJ making a 90 degree angle. Line LA is labeled 42 and line LF is labeled 3m. I hope this helps in solving the problem.
I started by writing 3m = 90 and got m=30 and 2m +3n = 90 where I put 30 in place of m and solved for n which was 20. My answer is m + n = 30 + 20 =50.
Thank you very much for taking the time to help me with this problem; we appreciate it very much.
YOU HAVE NOT GIVEN THE FIGURE..ASSUMING THE FOLLOWING
ALF IS A TRIANGLE WITH AF AS BASE.
J IS MIDPOINT OF AF AND LJ IS PERPENDICULAR TO AF.
AJ=34
JF=2M+3N
LJ=42
LF=3M
SINCE J IS MID POINT OF AF
AJ=JF
34 = 2M+3N..........................1
LJF IS RIGHT ANGLED TRIANGLE.
HENCE
LF^2=LJ^2+JF^2
(3M)^2=42^2+34^2=2920
M^2=2920/9
M = 18.01
2M+3N=34
3N =34 -2*18.01=-VE.....THE PROBLEM IS NOT CORRECT OR FIGURE IS NOT PROPER PLEASE GIVE THE FIGURE OR DESCRIBE THE FIGURE PROPERLY IN EVERY DETAILTO GIVE CORRECT ANSWER.