SOLUTION: the square root sign 3/5 how do get the square root of a fraction 6 sqare root sign 7*3 square root sign 5

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Question 5410: the square root sign 3/5
how do get the square root of a fraction
6 sqare root sign 7*3 square root sign 5

Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
This is really hard to read your question. If you put a few parentheses around some of the numbers, we would have a better idea what you mean. Nevertheless, I'll take a guess as to what I think you mean.

sqrt%283%2F5%29+
When you have a square root of a fraction, you can take the square root of the numerator and the square root of the denominator:
sqrt%283%2F5%29+=+%28sqrt%283%29%29%2F%28sqrt%285%29%29+

Then the tradition in math is to get rid of the radicals in the denominator by multiplying the numerator and denominator by something that will give you a perfect square in the denominator. In this case multiply by %28sqrt%285%29%29%2F%28sqrt%285%29%29+.


When you multiply the numbers you get:
=+%28sqrt%2815%29%29%2F%28sqrt%2825%29%29+, where you can rewrite the denominator with NO radicals:
+%28sqrt%2815%29%29%2F%28sqrt%2825%29%29+=%28sqrt%2815%29%29+%2F5

The second problem is 6sqrt%287%29%2A3sqrt%285%29
This is actually the product of four numbers. You can multiply these four numbers together in any order you wish, but it's a good idea to multiply the numbers that are outside the radicals and keep them outside the radical, and then multiply the numbers that are inside the radical and keep them inside the radical. It looks like this:
6sqrt%287%29%2A3sqrt%285%29
6%2A3+%2A+sqrt%287%29%2Asqrt%285%29
18+%2Asqrt%2835%29+

R^2 at SCC