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| Question 540980:  For the following function find the vertical, horizontal, and oblique asymptotes, if any.
 f(x)=(10x^2 - 11x - 3)/(3-5x)
 Answer by lwsshak3(11628)
      (Show Source): 
You can put this solution on YOUR website! For the following function find the vertical, horizontal, and oblique asymptotes, if any. f(x)=(10x^2 - 11x - 3)/(3-5x)
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 Vertical asymptotes:
 set denominator=0, then solve for x
 3-5x=0
 5x=3
 x=3/5
 Vertical asymptote: x=3/5
 Horizontal asymptote: none
 Oblique asymptote:
 Divide numerator by denominator: (by long division)
 (10x^2-11x-3)/(3-5x)=-2x+1 +Remainder=6
 Oblique asymptote: -2x+1 (a straight line with slope=-2 and y-intercept=1
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