SOLUTION: A store has 20 pounds of trail mix that is 3 part raisins to 2 part nuts. They have available another mix that is 1 part raisin to 3 part nuts. How much of this second mix should b
Algebra ->
Customizable Word Problem Solvers
-> Mixtures
-> SOLUTION: A store has 20 pounds of trail mix that is 3 part raisins to 2 part nuts. They have available another mix that is 1 part raisin to 3 part nuts. How much of this second mix should b
Log On
Question 540941: A store has 20 pounds of trail mix that is 3 part raisins to 2 part nuts. They have available another mix that is 1 part raisin to 3 part nuts. How much of this second mix should be added to the 20 pounds to give a mix that is equal parts of raisins and nuts?
I tried to add both ratios. (3:2)+ (1:3) = (4:5)
Then I added another (3:2) to (4:5) to get (7:7)
I just don't understand how I got this. HELP!! Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A store has 20 pounds of trail mix that is 3 part raisins to 2 part nuts. They have available another mix that is 1 part raisin to 3 part nuts. How much of this second mix should be added to the 20 pounds to give a mix that is equal parts of raisins and nuts?
----------
Follow the raisins:
raisins + raisins = raisins
(3/5)20 + (1/4)x = (1/2)(20+x)
Multiply thru by 20:
12*20 + 5x = 10(20+x)
12*20 + 5x = 10*20 + 20x
15x = 2*20
x = 8/3 lb (amt of the 2nd mix needed)
====================================
Cheers,
Stan H.
==============