SOLUTION: Find the number that is 3 more than twice the square root.

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Question 540815: Find the number that is 3 more than twice the square root.
Answer by fcabanski(1391) About Me  (Show Source):
You can put this solution on YOUR website!
x=2sqrt%28x%29%2B3


x-3=2sqrt%28x%29


Square both sides


%28x-3%29%5E2+=+4x


x%5E2+-+6x+%2B+9+=+4x


x%5E2+-+10x+%2B+9+=+0


%28x-9%29%28x-1%29=0


x-9=0 and x-1=0


x=9 and x=1


Try them in the original equation. 9 works. 1 works because recall that sqrt%28x%29 can be positive or negative. If it's negative (-1 * -1 = 1) then the original equation is:
1 = -2+3 which is correct.

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