SOLUTION: Marion walks 1 mph faster than Beth. They walk in opposite directions for 2 hours. They are then 30 miles apart. How fast so they each walk?

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Question 54079: Marion walks 1 mph faster than Beth. They walk in opposite directions for 2 hours. They are then 30 miles apart. How fast so they each walk?
Found 2 solutions by funmath, Nate:
Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
Draw a picture of Marion and Beth walking in opposite directions.
Can you see that if the are 30 miles apart you have to add their distances together to bet 30? I hope so.
The only formula you need is distance (d)=rate (r)*time(t)
d=rt
Let Beth's rate=x
Then Marion's rate=x+1
The time for both= 2
Your problem to solve is:
2(x+1)+2x=30
2x+2+2x=30
4x+2=30
4x+2-2=30-2
4x=28
4x/4=28/4
x=7
Beth's rate:x=highlight%287mph%29
Marion's rate:x+1=7+1=highlight%288mph%29
Check:2(7)+2(8)=30
14+16=30
30=30
Looks like we're right!
Happy Calculating!!!

Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
Remember: Rate * Time = Distance
Beth's rate = r
Beth's time = 2
Beth's Distance = 2r
Marion's rate = r + 1
Marion's time = 2
Marion's Distance = 2r + 2
2r + 2r + 2 = 30
4r + 2 = 30
4r = 28
r = 7
Beth's rate was 7mi/hr.
Marion's rate was 8mi/hr.