Question 540774: I need more help-big shocker!
Given the points A(3, -6) and B(9, 2). Find the equation of the perpendicular bisector through the line segment AB.
Can someone please help me solve this, please show me the steps!
Thanks much!
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Given the points A(3, -6) and B(9, 2). Find the equation of the perpendicular bisector through the line segment AB.
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Find slope and midpoint of AB:
slope = (2--6)/(9-3) = 8/6 = 4/3
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midpoint = (x,y)
x = (3+9)/2 = 6
y = (-6+2)/2 = -2
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Now find the eqution of the line
with slope = -3/4 passing thru point (6,-2)
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Form: y = mx + b
-2 = (-3/4)*6 + b
-2 = -9/2 + b
b = -2 + (9/2)
b = 5/2
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Equation you want:
y = (-3/4)x + (5/2)
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Cheers,
Stan H.
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