Question 540607: How many integral values of x satisfy inequality 8 < | 3x + 4| < 32
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! How many integral values of x satisfy inequality 8 < | 3x + 4| < 32
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solve for (3x+4)>0
8 < | 3x + 4| < 32
8 < 3x + 4 < 32
add-4
4 < 3x < 28
divide by 3
4/3 < x < 28/3
solution: (4/3,28/3)
number line:
<.......(4/3<===>28/3)...........>
..
solve for (3x+4)<0
8 < -3x - 4 < 32
add 4
12 < -3x < 36
divide by -3
-4 < x < -12
solution: (-∞,-12) U (-4,∞)
number line:
<===-12)......(-4====>
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