Question 540443: three times the square of a certain positive number exceeds six times the number by nine. Fine the number Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! let number be x
3x^2-6x=9
3x^2-6x-9=0
3x^2=-9x+3x-9=0
3x(x-3)+3(x-3)=0
(x-3)(3x+3)=0
x= 3 the positive value