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| Question 540383:  solve this system algebraically   y=x2-5
 y= x+1
 Answer by ankor@dixie-net.com(22740)
      (Show Source): 
You can put this solution on YOUR website! y = x^2 - 5 y = x + 1
 Since y = y, we can write it
 x^2 - 5 = x + 1
 x^2 - x - 5 - 1 = 0
 x^2 - x - 6 = 0; our old friend, the quadratic equation!
 Factors to
 (x-3)(x+2) = 0
 x = 3
 x = -2
 :
 Find y when x=3
 y = 3 + 1
 y = 4
 Find y when x=-2
 y = -2 + 1
 y = -1
 :
 You should check both pairs of solutions in the 1st equation
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