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Question 54013: If Martina leaves home at 9 A.M., bicycling at a rate of
24 mi/h. About two hours later, John leaves, driving at the rate of 48 mi/h. What will the time be when John catches up with Martina?
Found 2 solutions by checkley71, AnlytcPhil: Answer by checkley71(8403) (Show Source): Answer by AnlytcPhil(1806) (Show Source):
You can put this solution on YOUR website! If Martina leaves home at 9 A.M., bicycling at a rate of
24 mi/h. About two hours later, John leaves, driving at
the rate of 48 mi/h. What will the time be when John
catches up with Martina?
Make a DRT-chart:
Distance Rate Time
Martina
John
Fill in their rates (speeds)
Distance Rate Time
Martina 24
John 48
Let x be the time after 9 o'clock that John catches up
with Martina. So Martina's time is x hours, so fill
that in:
Distance Rate Time
Martina 24 x
John 48
Since John started two hours later, his time was 2 hours
less than Martina's time. So his time is x-2 hours. Fill
that in
Distance Rate Time
Martina 24 x
John 48 x-2
Now use the fact that Distance = Rate × Time to fill in
the two distances:
Distance Rate Time
Martina 24x 24 x
John 48(x-2) 48 x-2
They traveled the same distance, so we can set their
distances equal to each other:
24x = 48(x-2)
Solve that and get x = 4 hours.
Four hours after 9 AM is 1 PM.
Edwin
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