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Question 539802: Hi I am trying to figure out how to find the equation of a circle if the center is (4,4) and it passes through (-5,0)
I know there is an equation that goes with this where you subtract and ^2 power 4-(-5)^2 and (0-4)^2, but that is about all I have figured out & am not sure if it is correct. Thank you for your help.
LB
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Hi I am trying to figure out how to find the equation of a circle if the center is (4,4) and it passes through (-5,0)
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Standard form of equation of circle: (x-h)^2+(y-k)^2=r^2, (h,k)=(x,y) coordinates of center, r=radius
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Using given coordinates of center (4,4) and point (-5,0)
(-5-4)^2+(0-4)^2=r^2
(-9)^2+(-4)^2=r^2
81+16=r^2
97=r^2
r=√97
equation of circle: (x-4)^2+(y-4)^2=97
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