SOLUTION: The difference of two numbers is 20. the sum of three times the first and four times the second is 18. find the two numbers. So far this is what I have:
a-b=20
3a+4b=18
3(
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-> SOLUTION: The difference of two numbers is 20. the sum of three times the first and four times the second is 18. find the two numbers. So far this is what I have:
a-b=20
3a+4b=18
3(
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Question 539309: The difference of two numbers is 20. the sum of three times the first and four times the second is 18. find the two numbers. So far this is what I have:
a-b=20
3a+4b=18
3(2)+4(3)=18 but 2-3 does NOT equal 20.
I'm not sure how to figure this out. Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! The difference of two numbers is 20. the sum of three times the first and four times the second is 18. find the two numbers. So far this is what I have:
a-b=20
3a+4b=18
3(2)+4(3)=18 but 2-3 does NOT equal 20.
I'm not sure how to figure this out.
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Where did you get the 2 & 3?
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a-b=20 --? a = b+20
3a+4b=18
3(b+20) + 4b = 18
3b+60 + 4b = 18
7b = -42
b = -6
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a = 14
