Question 539272: In a race, if a dog going 37 mph gets a headstart of 12 yards, how long will it take a dog going 38 mph to catch up? Found 2 solutions by Alan3354, stanbon:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! In a race, if a dog going 37 mph gets a headstart of 12 yards, how long will it take a dog going 38 mph to catch up?
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The difference in speed is 1 mi/hr = 22/15 ft/sec
12 yds = 36 ft
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d = r*t
t = d/r = 36/(22/15) = 270/11 seconds
~ 24.5 seconds
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Note that the time would be the same if the speeds are both >0 and differ by 1 mi/hr.
You can put this solution on YOUR website! In a race, if a dog going 37 mph gets a headstart of 12 yards, how long will it take a dog going 38 mph to catch up?
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12 yds = 12/1760 = 0.0068 miles
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1st dog DATA:
rate = 37 mph ; distance = x miles ; time = x/37 hrs
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2nd dog DATA:
rate = 38 mph ; distance = x+0.0068 miles; time = (x+0.0068)/38 hrs
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Equation:
time = time
x/37 = (x+0.0068)/38
38x = 37x + 37*0.0068
x = 0.2516 miles
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time = x/37 = 0.2516/37 = 0.0068 hrs = 0.4080 minutes
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Cheers,
Stan H.
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