Question 53914: When graphed using polar coordinates, the center of a regular nonagon is at the origin and one vertex is at (6, 0 degrees) or (6, 0 radians). Find the polar coordinates of the other verticles in both degrees and radians.
Answer by venugopalramana(3286)   (Show Source):
You can put this solution on YOUR website! When graphed using polar coordinates, the center of a regular nonagon is at the origin and one vertex is at (6,0 degrees) or (6,0 radians). Find the polar coordiantes of the other vertices in both degrees and radians.
regular nonagon has 9 equal sides and equal angles.each side subtends an angle of 360/9 = 40 degrees or 2pi/9 radians at centre.all vertices are at equal distance from centre.hence if we take the given vertex as A = (6,0)...it means r=6 and theta = 0
for all other vertices r will be same and theta will increase by 40 degrees each..hence
B = (6,40) in degres..............(6,2pi/9) in radians
C = (6,80).........................(6,4pi/9)
D = (6,120).........................(6,6pi/9)
E = (6,160).........................(6,8pi/9)
G = (6,200)..........................(6,10pi/9)
H = (6,240)...........................(6,12pi/9)
I = (6,280)...........................(6,14pi/9)
J = (6,320)............................(6,16pi/9)
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