SOLUTION: The length of a rectangle is 2 km less than 3 times the width. If the perimeter is 68 km, what is the lenght of the rectangle

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Question 53904: The length of a rectangle is 2 km less than 3 times the width. If the perimeter is 68 km, what is the lenght of the rectangle
Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
Rectangles are four sided figures with opposite sides that are equal. Perimeter is the sum of the sides (add all the sides). So the perimeter of a rectangle is:
Perimeter(P)=length(L)+lenght(L)+width(W)+width(W)
P=L+L+W+W
P=2L+2W
Let the width=x
Then length is 2 less than (-2) 3 times (3*)the width(x)=3x-2
P=68 km (This is a BIG rectangle.)
Plug them into your formula and solve for x:
68=2(3x-2)+2(x)
68=6x-4+2x
68=(6+2)x-4
68=8x-4
68+4=8x-4+4
72=8x
72%2F8=8x%2F8
9=cross%288%29x%2Fcross%288%29
9=x
The width:x=9km
The length:3x-2=3(9)-2=27-2=25km
Happy Calculating!!!