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Question 539008: Find the point on the y-axis that is equidistant from (5,1) and (-3,-1).
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Find the point on the y-axis that is equidistant from (5,1) and (-3,-1)
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distance formula:
d^2=(x1-x2)^2+(y1-y2)^2
..
d1^2=d2^2
(x-5)^2+(y-1)^2=(x+3)^2+(y+1)^2
x-coordinate of point on y-axis=0
(0-5)^2+(y-1)^2=(0+3)^2+(y+1)^2
25+y^2-2y+1=9+y^2+2y+1
-4y=-16
4y=16
y=4
..
ans:
Point on the y-axis=4
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