SOLUTION: which equation describes the line that passes through the point (4,-2) and is perpendicular to the line 4x-7y=28

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Question 538744: which equation describes the line that passes through the point (4,-2) and is perpendicular to the line 4x-7y=28
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
4x-7y=28---> 7y=4x-28---> y=%284%2F7%29x-4 shows the slope of the line is 4.
The perpendicular line has a slope of 1%2F%28-4%29=-1%2F4.
The point-slope form of the perpendicular line through (4, -2) written using point (4, -2) and slope -1/4 is
y-%28-2%29=%28-1%2F4%29%28x-4%29 or y=2=-%281%2F4%29x%2B1
There are as many point-slope forms as points in a line (infinity), but there is only one slope-intercept form of the equation, starting with "y=" and that is:
y=-%281%2F4%29x-1