Question 53851This question is from textbook Intermediate Algebra
: My problem is (3/4, 8/3) and (2/5, 2/3.
I am supposed to find the slope and put the problem into slope intercept form and then into standard form (Ax+By=C).
Thank you!
This question is from textbook Intermediate Algebra
Found 2 solutions by stanbon, ankor@dixie-net.com:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! My problem is (3/4, 8/3) and (2/5, 2/3).
I am supposed to find the slope and put the problem into slope intercept form and then into standard form (Ax+By=C).
-----------
slope = [8/3 - (2/3)]/[(2/5)-(3/4)]
= 2/(-7/20)
= -40/7
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2/3 = (-40/7)(2/5)+b
2/3=-80/35 + b
b= (2/3)+(80/35)
b= [70+240]/105
b=2
EQUATION:
y=(-40/7)x+2
To put it in standard form multiply thru by 7 to get:
7y=-40x+14
40x+7y=14
Cheers,
Stan H.
Answer by ankor@dixie-net.com(22740)  (Show Source):
You can put this solution on YOUR website! :
My problem is (3/4, 8/3) and (2/5, 2/3).
:
I am supposed to find the slope and put the problem into slope intercept form and then into standard form (Ax+By=C).
:
the slope equation: m = 
:
In this problem x1 = 3/4; y1 = 8/3, x2 = 2/5, y2 = 2/3
:
Let's get rid of these annoying fractions, mult them all by 60, it won't affect the value of the slope
Then we have x1 = 45, y1 = 160, x2 = 24, y2 = 40
m =  = =
:
m = (40/7) x1 = 3/4, y1 = 8/3
:
Substitute in point/slope equation: y - y1 = m(x-x1)
:
y - 8/3 = (40/7)m(x - 3/4)
:
y - 8/3 = (40/7)x - (40/7)(3/4)
:
y - 8/3 = (40/7)x - 120/28
:
y - 8/3 = (40/7)x - 30/7 reduced the fraction
:
y = (40/7)x - 30/7 + 8/3
:
y = (40/7)x - 90/21 + 56/21
:
y = (40/7)x - 34/21; this is the slope/intercept equation (y = mx+b)
:
-21y = -120x + 34; multiplied eq by -21
:
120x - 21y = 34 is the standard form
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