SOLUTION: I need STEPS on how to do this! A boy ran to the store at 6 miles per hour, he walked back at 4 miles per hour. If the roundtrip took hom 10 minutes, how far is the store?

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Question 537930: I need STEPS on how to do this!
A boy ran to the store at 6 miles per hour, he walked back at 4 miles per hour. If the roundtrip took hom 10 minutes, how far is the store?

Found 2 solutions by Earlsdon, Alan3354:
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Use the distance formula:
d+=+r%2At where: d = distance, r = rate(speed), and t = time of travel.
Going to the store:
d%5B1%5D+=+r%5B1%5D%2At%5B1%5D Substitute: r%5B1%5D+=+6
d%5B1%5D+=+6%2At%5B1%5D
Returning returning from the store:
d%5B2%5D+=+r%5B2%5D%2At%5B2%5D Substitute r+=+4
d%5B2%5D+=+4%2At%5B2%5D
Now the total time is t%5B1%5D%2Bt%5B2%5D+=+10 so t%5B2%5D+=+10-t%5B1%5D and the distance to the store is the same as the distance back, so d%5B1%5D+=+d%5B2%5D
So now we can write:
6%2At%5B1%5D+=+4%2At%5B2%5D Substitute t%5B2%5D+=+10-t%5B1%5D
6%2At%5B1%5D+=+4%2810-t%5B1%5D%29 Simplify and solve for t%5B1%5D
6%2At%5B1%5D+=+40-4%2At%5B1%5D Add 4%2At%5B1%5D to both sides.
10%2At%5B1%5D+=+40 Divide both sides by 10.
t%5B1%5D+=+4 Now substitute this into the first equation and solve for d%5B1%5D
d%5B1%5D+=+6%2At%5B1%5D Substitute t%5B1%5D+=+4
d%5B1%5D+=+6%2A4
d%5B1%5D+=+24
The store is 24 miles away.

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
A boy ran to the store at 6 miles per hour, he walked back at 4 miles per hour. If the roundtrip took hom 10 minutes, how far is the store?
---------------
Avg speed of the round trip is
2*6*4/(6+4) = 4.8 mi/hr
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d = r*t = 4.8 mi/hr * (10/60) hr = 0.8 miles round trip
--> 0.4 miles each way