SOLUTION: Can someone help me on this problem? I need to identify the rate, base, and amount in the following application. You do not need to solve the applications at this point.

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Question 53790: Can someone help me on this problem?
I need to identify the rate, base, and amount in the following application. You do not need to solve the applications at this point.
A chemist has 300 milliliters (mL) of solution that is 18% acid. How many milliliters of acid are in the solution?
Thanks, Ashley
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
18%=.18 THEN .18*300ML=54 ML OF ACID OR 54/300=.18 OR 18%