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Question 537847: Hello there! I need help with a few problems i have ask everyone even my teacher and the are not giving me the information i need so i can do my homework. so if you dont mind if can you let me. The Problems are: SOLVING QUADRATRIC EQUATIONS WITH SQUARE ROOTS.
1.-6m^2=-414
2.7x^2=21
3.m^2+7=88
4.-5x^2=-500
5.-7n^2=-448
6.-2k^2=-162
7.x^2-5=73
8.16n^2=49
Thanks and if you cant answer all of the questions its okay but i really need help because i cant tell my mom im failing math. <3
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! 1.-6m^2 = -414
divide both sides by -6, this simplifies and changes the signs so we have:
m^2 = 
m^2 = +69
Find the square root of both sides
m = +/-  ; not a perfect square so we can just leave like this
:
2. 7x^2 = 21
Divide both sides by 7, leaves us with a simple equation
x^2 = 3
x = +/- 
:
3. m^2 + 7 = 88
subtract 7 from both sides
m^2 = 88 - 7
m^2 = 81
m = +/- 
m = +/- 9
:
4. -5x^2 = -500
Divide both sides by -5, simplifies and changes the signs, so we have:
x^2 = +100
x = +/- 
x = +/- 10
:
5.-7n^2=-448
Divide both sides by -7
n^2 = +64
n = +/- 
n = +/- 8
:
6.-2k^2 = -162
you should be catching on by now, divide by -2, and do as we did above
:
7. x^2 - 5 = 73
add 5 to both sides
x^2 = 73 + 5
x^2 = 78
x = +/-
:
8. 16n^2=49
divide both sides by 16,
n^2 = 
find the square root of both sides
n = +/-
note that we can find the square root of the numerator, 7; and denominator, 4
so we have:
n = +/- 
:
:
Did this shed some light on this stuff? Let me know how you do, please. C
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