SOLUTION: A committee of four people are to be chosen from six Democrats and four Republicans. Find the probability that two are Democrats and two are Republicans. Express your answer as a f
Algebra ->
Probability-and-statistics
-> SOLUTION: A committee of four people are to be chosen from six Democrats and four Republicans. Find the probability that two are Democrats and two are Republicans. Express your answer as a f
Log On
Question 537502: A committee of four people are to be chosen from six Democrats and four Republicans. Find the probability that two are Democrats and two are Republicans. Express your answer as a fraction reduced to lowest terms Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A committee of four people are to be chosen from six Democrats and four Republicans. Find the probability that two are Democrats and two are Republicans. Express your answer as a fraction reduced to lowest terms
----
# of ways to succeed: 6C2*4C2 = 15*6 = 90 ways
---
# of randomly chosen committee: 10C4 = 210
---
P(2Dems and 2Reps) = 90/210 = 9/21 = 3/7
========================
Cheers,
Stan H.
========================
(