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Question 537423: how can i write x=y2-2y-15 in standard form and graph it
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! how can i write x=y2-2y-15 in standard form and graph it
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x=y2-2y-15
complete the square
x=(y^2-2y+1)-15-1
x=(y-1)^2-16
This is an equation of a parabola which opens rightwards of the standard form: x=A(y-k)^2+h, with (h,k) being the (x,y) coordinates of the vertex.
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For given equation of a parabola:
vertex: (-16,1)
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y-intercept:
set x=0
(y-1)^2-16=0
(y-1)^2=16
take sqrt of both sides
y-1=±√16=±4
y=1±4
y=5 or -3
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x-intercept
set y=0
x=-15
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You now have coordinates of the vertex, the y-intercepts, x-intercept and knowledge that it is a parabola that opens rightwards, information with which you should be able to graph the given function.
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