Question 537358: Two scooters travel from the same point in the same direction, leaving at the same time. The faster scooter travels at twice the speed of the slower scooter. After three seconds, the faster scooter has traveled 6 feet more than the slower scooter. What is the speed of each scooter?
Answer by algebrahouse.com(1659)   (Show Source):
You can put this solution on YOUR website! "Two scooters travel from the same point in the same direction, leaving at the same time. The faster scooter travels at twice the speed of the slower scooter. After three seconds, the faster scooter has traveled 6 feet more than the slower scooter. What is the speed of each scooter?
Distance = rate x time
D = rt
slower scooter
r = r
t = 3 {after 3 seconds}
D = 3r {distance = rate x time}
faster scooter
r = 2r {twice the slower scooter}
t = 3 {after 3 seconds}
D = 6r {distance = rate x time}
After 3 seconds the faster scooter was 6 feet in front of slower scooter:
3r + 6 = 6r {slower scooter distance plus 6 = faster scooter distance}
6 = 3r {subtracted 3r from both sides}
r = 2 {divided both sides by 3}
2r = 4 {substituted 2, in for r, into 2r}
slower scooter's speed is 2
faster scooter's speed is 4
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