|
Question 537211: The height (in feet) of the water level in a reservoir over a 1 year period is modeled by the function H(t) = 2.4(t - 10)2 + 15, where t = 1 represents January, t = 2 represents February, and so on. How low did the water level get that year, and when did it reach the low mark?
Thank you in advance!
Answer by nerdybill(7384)   (Show Source):
You can put this solution on YOUR website! The height (in feet) of the water level in a reservoir over a 1 year period is modeled by the function H(t) = 2.4(t - 10)2 + 15, where t = 1 represents January, t = 2 represents February, and so on. How low did the water level get that year, and when did it reach the low mark?
The vertex of H(t) = 2.4(t - 10)2 + 15 gives you the low point:
equation given is in the "vertex" form:
y= a(x-h)^2+k
vertex is at (10,15)
when did it reach the low mark?
t = 10 (October)
How low did the water level get:
h(t) = 15 feet
|
|
|
| |
