SOLUTION: please help me to find the LCD for the fractions: 1/3, 5/12, 7/18 (i came up with : 3*2^2*3^2 = 108 which was incorrect, the teacher marked out my 3, and my 108)

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: please help me to find the LCD for the fractions: 1/3, 5/12, 7/18 (i came up with : 3*2^2*3^2 = 108 which was incorrect, the teacher marked out my 3, and my 108)      Log On


   



Question 536802: please help me to find the LCD for the fractions:
1/3, 5/12, 7/18
(i came up with : 3*2^2*3^2 = 108 which was incorrect, the teacher marked out my 3, and my 108)

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
The LCD of the fractions is equal to the LCM of the denominators.

The denominators are 3, 12, and 18


So let's list out the prime factorizations of each:



3: 3 ** Note: 3 is prime and there is only one factor (other than 1)

12: 2*2*3

18: 2*3*3

Now highlight the unique and most occurring factors. These factors are 2*2 and 3*3. Multiply them out to get 2*2*3*3 = 4*9 = 36


So the LCM of 3, 12, and 18 is 36. This is the smallest number that all 3 denominators go into evenly.


So the LCD of the fractions is 36


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