SOLUTION: The area of a rectangular wall in a classroom is 165 square feet. Its length
is 4 feet longer than its width. Find the width of the wall of the
classroom.
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-> SOLUTION: The area of a rectangular wall in a classroom is 165 square feet. Its length
is 4 feet longer than its width. Find the width of the wall of the
classroom.
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Question 536672: The area of a rectangular wall in a classroom is 165 square feet. Its length
is 4 feet longer than its width. Find the width of the wall of the
classroom. Answer by algebrahouse.com(1659) (Show Source):
You can put this solution on YOUR website! "The area of a rectangular wall in a classroom is 165 square feet. Its length
is 4 feet longer than its width. Find the width of the wall of the
classroom."
x = width
x + 4 = length {the length is 4 longer than the width}
Area of a rectangle = width x length
x(x + 4) = 165 {area of a rectangle is width x length}
x² + 4x = 165 {used distributive property}
x² + 4x - 165 = 0 {subtracted 165 from both sides}
(x + 15)(x - 11) = 0 {factored into two binomials}
x + 15 = 0 or x - 11 = 0 {set each factor equal to 0}
x = -15 or x = 11 {subtracted 15 and added 11}
x = 11 {width of a rectangle cannot be negative}
