SOLUTION: Please help me find a limit of an=n^2(n!)/(n+2)! the second is an=e^n+e^-n/e^2n-1

Algebra ->  Sequences-and-series -> SOLUTION: Please help me find a limit of an=n^2(n!)/(n+2)! the second is an=e^n+e^-n/e^2n-1      Log On


   



Question 536616: Please help me find a limit of an=n^2(n!)/(n+2)! the second is an=e^n+e^-n/e^2n-1
Answer by AnlytcPhil(1806) About Me  (Show Source):
You can put this solution on YOUR website!
a%5Bn%5D = n%5E2%28n%21%29%2F%28n%2B2%29%21 = = = n%5E2%2F%28n%2B2%29%28n%2B1%29 = n%5E2%2F%28n%5E2%2B3n%2B1%29
matrix%283%2C1%2C+++%22%22%2Clim%2C%22x-%3Eoo%22%29%28a%5Bn%5D%29 = matrix%283%2C1%2C+++%22%22%2Clim%2C%22x-%3Eoo%22%29%28matrix%281%2C1%2Cn%5E2%2F%28n%5E2%2B3n%2B1%29%29%29 =matrix%283%2C1%2C+++%22%22%2Clim%2C%22x-%3Eoo%22%29%28matrix%281%2C1%2C%28n%5E2%2Fn%5E2%29%2F%28n%5E2%2Fn%5E2%2B3n%2Fn%5E2%2B1%2Fn%5E2%29%29%29 = matrix%283%2C1%2C+++%22%22%2Clim%2C%22x-%3Eoo%22%29%28matrix%281%2C1%2C1%2F%281%2B3%2Fn%2B1%2Fn%5E2%29%29%29 = 1%2F%281%2B0%2B0%29 = 1
`
For the other one, "an=e^n+e^-n/e^2n-1", I can't tell what parts go with the
exponents, the numerator, and the denominator. You didn't put parentheses
to show what goes where. Post again with parentheses around all exponents,
all numerators, and all denominators so we can tell where they start
and end.
Edwin