SOLUTION: At the begining of a walk, Steve and Eve are 6.6 mies apart. If they leave at the same time and wak in the same direction, Steve overtakes Eve in 11 hours. If they walk towards eac
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-> SOLUTION: At the begining of a walk, Steve and Eve are 6.6 mies apart. If they leave at the same time and wak in the same direction, Steve overtakes Eve in 11 hours. If they walk towards eac
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Question 536422: At the begining of a walk, Steve and Eve are 6.6 mies apart. If they leave at the same time and wak in the same direction, Steve overtakes Eve in 11 hours. If they walk towards each other, they meet in 1 hour. What are their speeds? Answer by mananth(16949) (Show Source):
You can put this solution on YOUR website! steve speed= x
eve speed =
when they are walking in same direction the effective speed = x-y
d=6.6
t=11 hours
t=d/r
11= 6.6/(x-y)
11x-11y=6.6
x-y=0.66-------------------1
when they are walking towards each other speed = x+y
1=6.6/(x+y)
x+y=6.6---------------------2
Add equation (1) & (2)
2x=7.20
x=3.6 mph ----- steve's speed
plug x in (1)
3.6-y=0.66
3.6-0.66=y
2.94 =y -----------eve's speed
