SOLUTION: A train is traveling at 22 m/s when it passes your town. Where will the train be 30 minutes later? Imagine that the train was 300 meters south of the your town when it was fi

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: A train is traveling at 22 m/s when it passes your town. Where will the train be 30 minutes later? Imagine that the train was 300 meters south of the your town when it was fi      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 536239: A train is traveling at 22 m/s when it passes your town. Where will the train be 30 minutes later?

Imagine that the train was 300 meters south of the your town when it was first observed. (We will assume that south is a negative direction). What is the trains POSITION at 50 seconds? How FAR did it travel in total though?
Answer by fcabanski(1391) About Me  (Show Source):
You can put this solution on YOUR website!
Distance formula: D = rt where r is the rate (speed) and t is time.


In this case for part A:

D = what must be found.

r = 22 m/s

t = 30 minutes * 60 seconds/minute = 1800 seconds. (Convert minutes to seconds because the speed is given in meters per second.)


D = 22*1800 = 39600 meters = 39.6 kilometers from town.


Part B: Use D=rt to find how far the train traveled in 50 seconds.

D = what must be found.

r = 22 m/s

t = 50 seconds.


D = 22 * 50 = 1100 meters.


The train began 300 meters south of town, which the problem specifies as -300. It moved 1100 meters north, which is +1100, so its position is now:


1100-300= 800. For the problem, +800 means 800 meters north of town.

I provide online tutoring ($30/hr) and personal problem solving
($3.50-$5.50 per problem. Contact me (check the profile "website" which is
my email address.