SOLUTION: Simplify complex fractions (1 - 2/r - 8/r^2)/ (1 - 1/r - 6/r^2) Please show me how it's done. I have several more to do and can follow this example. Thanks

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: Simplify complex fractions (1 - 2/r - 8/r^2)/ (1 - 1/r - 6/r^2) Please show me how it's done. I have several more to do and can follow this example. Thanks      Log On


   



Question 53610: Simplify complex fractions
(1 - 2/r - 8/r^2)/ (1 - 1/r - 6/r^2)
Please show me how it's done. I have several more to do and can follow this example. Thanks

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
(1 - 2/r - 8/r^2)/ (1 - 1/r - 6/r^2)
Change fractions to a common denominator of r^2 as follows:
[(r^2 -2r-8)/r^2]/[(r^2-r-6)/r^2]
Invert the denominator and multiply to get:
[(r^2 -2r-8)/r^2] * [(r^2)/(r^2-r-6)]
Cancel the r^2 which are common to numerator and denominator to get:
[r^2-2r-8]/[r^2-r-6]
Factor where you can, as follows:
[(r-4)(r+2)]/[(r-3)(r+2)]
Cancel the (r+2) which is common to numerator and denominator to get:
(r-4)/(r-3)
Cheers,
Stan H.