You can put this solution on YOUR website! (x+3)/x > 0
When x+3=0 then the function = 0. x+3=0 when x=-3.
when the denominator=0 then the function is undefined. The denominator=0 when x=0.
.
when x<-3: make x=-5: (-5+3)/-5 = 2/5 the function > 0
when x>-3 and x<0 make x=-1: (-1+3)/-1 = -2/1 = -2 the function < 0
when x>0: make x=1: (1+3)/1 = 4 the function > 0
ANSWER: X(-infinity, -3) U (0, infinity)
.
Ed
.
