SOLUTION: I have the equation y=-x^2-8x-15 and i am trying to graph it. How do I find the vertex?

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: I have the equation y=-x^2-8x-15 and i am trying to graph it. How do I find the vertex?      Log On


   

Question 535971: I have the equation y=-x^2-8x-15 and i am trying to graph it. How do I find the vertex?
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
y=-x^2-8x-15
The vertex for x=-b/2a=8/-2=-4
y(-4)=-16+32-15=1 vertex for y
(-4, 1) Vertex
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Ed
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graph%28500%2C500%2C-10%2C10%2C-10%2C10%2C-x%5E2-8x-15%29