SOLUTION: A plance travels 2100 km with the wind. The return trip against the wind is 1 h longer. If the rate of the plane in still air is 325 km/h, find the rate of the wind.
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Question 535921: A plance travels 2100 km with the wind. The return trip against the wind is 1 h longer. If the rate of the plane in still air is 325 km/h, find the rate of the wind. Answer by mananth(16946) (Show Source):
Speed with wind 325 + x
Speed against wind 325 - x
Distance = 2100 km
t=d/r
Time against wind - Time with Wind = 1
2100 /( 325-x)- 2100/(325+x ) = 1
LCD= ( 325 - x)( 325 + x)
Multiply equation by LCD
We get
2100 ( 325+x)- 2100(325-x)=1*(325-x)(325+x)
682500+2100x -682500+2100x=1*( 105625 -x^2)
4200 x =105625 -1x^2
-1 x^2 -4200 x + 105625 = 0
Find the roots of the equation by quadratic formula
