SOLUTION: If computer a can process 10 pictures in 180 sec, and working toghether with computer b, processes them in 100 sec, how long does it take for b to process the same amount of pictur

Algebra ->  Rate-of-work-word-problems -> SOLUTION: If computer a can process 10 pictures in 180 sec, and working toghether with computer b, processes them in 100 sec, how long does it take for b to process the same amount of pictur      Log On


   



Question 535888: If computer a can process 10 pictures in 180 sec, and working toghether with computer b, processes them in 100 sec, how long does it take for b to process the same amount of pictures
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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If computer a can process 10 pictures in 180 sec, and working together with computer b, processes them in 100 sec,
how long does it take for b to process the same amount of pictures
:
let b = time required by b alone
let the completed job = 1 (10 pics processed)
:
A typical shared work equation
100%2F180 + 100%2Fb = 1
mult by 180b
180b*100%2F180 + 180b*100%2Fb = 180b
Cancel the denominators and you have
100b + 180(100) = 180b
18000 = 180b - 100b
18000 = 80b
b = 18000%2F80
b = 225 sec alone