Question 53575: Suppose you and a friend are standing on an ice-skating rink and you push off against each other. You will go in opposite directions, but the product of your speed and your weight will be the same as the product of your friend's speed and her weight.
a. suppose the common value of this product is 483, when the units are pounds and miles per hour. Let w = your weight in pounds and let s = your speed in miles per hour. Write an equation that models the situation. Is this an example of inverse variation?
b. Let's say you weigh 105 lbs. How fast will you be traveling after you push off
c. friend weighs 75 lbs. how fast will she be going after you push off?
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! the product of your speed and your weight will be the same as the product of your friend's speed and her weight.
a. suppose the common value of this product is 483, when the units are pounds and miles per hour. Let w = your weight in pounds and let s = your speed in miles per hour. Write an equation that models the situation. Is this an example of inverse variation?
ws=483
Yes, w and s vary inversely.
----------------------
b. Let's say you weigh 105 lbs. How fast will you be traveling after you push off.
105s=483
s=4.6 mph
------------
c. friend weighs 75 lbs. how fast will she be going after you push off.
75s=483
s=6.44 mph
Cheers,
Stan H.
|
|
|