SOLUTION: I'm going to try this one more time. My question is:
What is the area of a TRIANGLE which has a base of 16, and the 2 other angles are BOTH 10.5. I don't know how else to ask th
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-> SOLUTION: I'm going to try this one more time. My question is:
What is the area of a TRIANGLE which has a base of 16, and the 2 other angles are BOTH 10.5. I don't know how else to ask th
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Question 535515: I'm going to try this one more time. My question is:
What is the area of a TRIANGLE which has a base of 16, and the 2 other angles are BOTH 10.5. I don't know how else to ask this?
The bottom (base) of the triangle is 16.
The left angle, coming up from the base is 10.5.
The right angle, coming up from the base is 10.5.
PLEASE, I just need to know what the area is of this triangle. Thank you. Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! The altitude of the triangle bisects the base of an isoscles triangle.
When you draw a line from the opposite vetex to the base 2 congruent triangles are formed by the height.
Total base = 16
half the base = 8
the angle = 10.5
Find the height of the triangle by tan value
Tan = height /base
Tan (10.5) = height / 8
8 * tan 10.5= height
height = 1.48
Area = 1/2 * 16 * 1.48
Area = 11.84 sq. units
