SOLUTION: I need to use long division to divide (2x^2 + x - 13) by (x + 3) Thanks for your help

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Question 5355: I need to use long division to divide
(2x^2 + x - 13) by (x + 3)
Thanks for your help

Answer by Abbey(339) About Me  (Show Source):
You can put this solution on YOUR website!
Set this up like a long division problem
(I am going to use the square root sign on the computer)
%28x%2B3%29+sqrt%282x%5E2%2Bx-13%29
The steps for long division are:
Step 1. divide the first term of the numerator by the first term of the denominator
Step 2. multiply both terms in the denominator by the result of step 1.
Step 3. subtract the result of step 2 from the original numerator
Step 4. Bring the next number from the numerator down and add to the result of step 3
repeat the process
perform the division part of the long division on the FIRST term of the numerator (the 2x%5E2 in the %282x%5E2%2Bx-13%29 and the first term of the denominator (the X in the (x+3)) , but perform the multiplication and subtraction on BOTH terms in the denominator (both the x and the 3 in the (x+3) term):
Step 1. divide 2x%5E2 by x and get 2x
Step 2. multiply (x+3) by 2x to get 2x%5E2%2B6x
Step 3. subtract 2x%5E2%2B6x from 2x%5E2%2Bx-13 and get -5x
Step 4. Bring down the next term -13 and add it to -5x to get -5x-13
Repeat:
Step 1. divide -5x by x to get -5
Step 2. multiply -+5 by x%2B3 to get -5x-15
Step 3. subtract -5x-15 from -5x-13 and get 2 as a remainder
The answer will is 2x-5 with a remainder of 2%2F%28x%2B3%29